Physics Help Needed ASAP? PHYSICS: Lens and Images, BEST ANSWER WILL BE PICKED?

Hey There! I am having a hard time with my Physics homework. I have a test on Monday and I was given a review sheet and I can't seem to answer the last question! I been trying and trying!! Please help. I keep getting the wrong answers! If it is possible could you show the work or formulas so I can understand it better! Thanks.





You have a converging lens with a focal length of 24.4cm. You place a 2.0 cm tall object 35.8cm in front of the lens.





a) Where is the image located?


__cm





b) What kind of image is it?





virtual or real?





c) What is the image height?


__cm





d) What is the orientation of the image?





upright or inverted?


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You have a diverging lens with a focal length of 23cm. You place a 2.0 cm tall object 41.6cm in front of the lens.





a) Where is the image located?


__cm





b) What kind of image is it?





real or virtual?





c) What is the image height?


__cm





d) What is the orientation of the image?





inverted or upright?





~~~


Thanks for your help=)

Physics Help Needed ASAP? PHYSICS: Lens and Images, BEST ANSWER WILL BE PICKED?
Hmmm many questions. The di for a converging lens is given by di = 1/(1/f - 1/do) .





a. Substituting we get di = 76.625 cm.





b. If the object distance is greater than the focal length, the image is real and di is positive.





c. Image height is found by using the magnification = -di/do


substituting we get -4.2807 cm





d. The negative sign means the image is inverted.





For a diverging lens, the formulas are the same but the focal length is a negative quantity.





a. image distance is -14.811 cm.





b. the image is virtual





c. 0.71207 cm





d. the image is upright





Hope this helps, but please try to use the lens equation yourself so you understand how these answers were obtained. Mike R

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