ok... here are the problems please explain and show work too
Find the equations in standard form(Ax+by+c=0) of the tangent and the normal to the graph of (x+1)^2+(y-2)^2=36 at (-1,8)
Identify the graph of X^2-6xy+9y^2=7 then find the angle or rotation about the origin to the nearest degree
Math help... for a virtual chocolate chip cookie...please?
(x+1)^2+(y-2)^2=36 at (-1,8)
This is a circle; radius 6 centered at (-1,2)
So the tangent at the point (-1,8) will be perpendicular to the line from the center (-1,2) to (-1,8) (and this radius will also be the normal).
That line has the equation x=-1. So the tangent to the original curve at that point will be of the form y=k; since we know that (-1,8) is on that line, the tangent will be
y = 8.
Tangent: y = 8
Normal: x=-1
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